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12x^2-144x+384=0.
a = 12; b = -144; c = +384;
Δ = b2-4ac
Δ = -1442-4·12·384
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-144)-48}{2*12}=\frac{96}{24} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-144)+48}{2*12}=\frac{192}{24} =8 $
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